prove that: ` 4 cot^2(45^ @) - sec^2(60^ @)+ sin^2(30^ @) = 1/8`

The value of x, if x cos ^(2) 45 ^(@) - sec ^(2) 60^(@) + sin ^(2) 30^(@) = (1)/(8), is

Prove that : cot^2 60^@+ sin^2 45^@+ sin^2 30^@+ cos^2 90^@=13/12 .

The value of (4cos^2 60^@ + 3 sec^2 30^@ -cot^2 45^@)/(cos^2 60^@ + sin^2 60^@) is:

The numerical value of ( cos^2 45^@ ) /( sin ^2 60 ^@) +( cos ^2 60^@ )/( sin ^2 45 ^@ ) -(tan ^2 30 ^@ )/( cot^2 45^@ ) -( sin^2 30 ^@ )/( cot^2 30^@) is

Prove that : 3cosec^(2)60^(@)-2cot^(2)30^(@)+sec^(2)45^(@)=0 .

Prove that : 3cosec^(2)60^(@)-2cot^(2)30^(@)+sec^(2)45^(@)=0 .

Prove that cot^2 60^@+sin^2 45^@ +sin^2 30^@+cos^2 90^@=(13)/(12)

Using tables evaluate the following: 4cot45^@-sec^2 60^@+sin 30^@

Prove that : cosec 60^@ cot 30^@ tan 60^@= 2 sec^2 45^@ cos30^@ .