tan(A+B)(tan A-B)=

In a triangle ABC , right angled at A ,the altitude through A and internal bisector of /_A have lengths 3 and 4 respectively. Find the length of median through A. Given that tan(A+B)=(tan A+tan B)/(1-tan A tan B),tan(A-B)=(tan A-tan B)/(1+tan A tan B)

In a triangle ABC ,right angled at A ,the altitude through A and internal bisector of /_A have lengths 3 and 4 respectively. Find the length of median through A . (Given that tan(A+B)=(tan A+tan B)/(1-tan A tan B),tan(A-B)=(tan A-tan B)/(1+tan A*tan B))

Prove that tan(A-B)=(tan A-tan B)/(1+tan A*tan B) , if A=60° & B=45°.

If A=60⁰ and B=30⁰ , verify that tan (A-B)=(tan A-tan B)/(1+tan A tan B)

tan(B-C)+tan(C-A)+tan(A-B)=tan(B-C)tan(C-A)tan(A-B)

tan(B-C)+tan(C-A)+tan(A-B)=tan(B-C)tan(C-A)tan(A-B)

For all values of A and Btan(A+B)=(tan A+tan B)/(1-tan A tan B) and tan(A-B)=(tan A-tan B)/(1+tan A tan B)

(tan A + tan B) / (tan A-tan B) = (sin (A + B)) / (sin (AB))

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , (tan40^(@)+2tan10^(@))*(tan70^(@)-Tan20^(@))=

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , x= Tan""(5 pi)/(28)+2Tan""(pi)/(7) Then x