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" 19."(1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2...

" 19."(1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2));y=0" Thde "x=1

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(1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2));y=0 if x=1

(1 + x^(2))(dy)/(dx) + 2xy = (1)/(1 + x^(2)), y = 0 when x= 1

(1 + x^(2))(dy)/(dx) + 2xy = (1)/(1 + x^(2)), y = 0 when x= 1

the particular solution of (1 + x^(2))(dy)/(dx) + 2xy = (1)/(1 + x^(2)), y = 0 when x= 1 is

(dy)/(dx) = (2xy)/(x^(2)-1-2y)

(dy)/(dx) = (2xy)/(x^(2)-1-2y)

(dy)/(dx) = (2xy)/(x^(2)-1-2y)

(dy)/(dx)-(xy)/(1-x^(2))=(1)/(1-x^(2))