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When electronic transition occurs from h...

When electronic transition occurs from higher energy state to lower energy state with energy difference equal to `Delta E` electron volts, the wavelength of the line emitted is approximately equal to

A

`(12397)/(Delta E) xx 10^(-10) m`

B

`(12397)/(Delta E) xx 10^(10) m`

C

`(12397)/(Delta E) xx 10^(-10) cm`

D

`(12397)/(Delta E) xx 10^(10) cm`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda = (hc)/(Delta E)`
`= (6.62 xx 10^(-34)(Js) xx 3 xx 10^(8)(ms^(-1)))/(Delta E xx 1.602 xx 10^(-19))`
`= (12.3970 xx 10^(-7))/(Delta E)m = (12397 xx 10^(-10))/(Delta E)m`
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