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The orbital configuration of .(24)Cr is ...

The orbital configuration of `._(24)Cr` is `3d^(5) 4s^(1)`. The number of unpaired electrons in `Cr^(3+) (g)` is

A

3

B

2

C

1

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
`Cr^(3+)` has configuration `3d^(3) 4s^(0)`.
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