Home
Class 11
CHEMISTRY
For an orbital with n = 2, l = 1, m = 0 ...

For an orbital with n = 2, l = 1, m = 0 there is/are

A

one planar node

B

one region of maximum probability

C

two lobes of same size about the nucleus

D

all the above statements are correct

Text Solution

Verified by Experts

The correct Answer is:
D

`because` for l =2, the shape of orbital is p.
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    DINESH PUBLICATION|Exercise Revision Questions|258 Videos
  • ATOMIC STRUCTURE

    DINESH PUBLICATION|Exercise Selected Straight Objective Type MCQs|70 Videos
  • APPENDIX

    DINESH PUBLICATION|Exercise Completion Reactions|15 Videos
  • BIOMOLECULES

    DINESH PUBLICATION|Exercise Reason|1 Videos

Similar Questions

Explore conceptually related problems

The orbital with n=3 and l=2 is

The shape of the orbital with l = 1 and m = 0 is

The shape of the orbital with the value of l = 2 and m = 0 is

Describe the orbital with n = 4 and l=0

Given below are the sets of quantum numbers for given orbitals .Name these orbitals a. n = 2 l = 1 m = -1 b. n = 4 l = 2 m = 0 c. n = 3 l = 1 m = +- 1 d. n = 4 l = 0 m = 0 e. n = 3 l = 2 m = +- 2

The orbital having n = 2,l=p 12 and n= 0 will be desigrated as

Describe the orbital having n=2,l=1 and m=0 .

The orbital n = 6,l= 2 and m= 0 will be designated as

From the following sets quantum number state which are possible. Explain why the other are not permitted ? a. n = 0, l = 0, m= 0, s = + 1//2 b. n = 1, l = 0, m= 0, s = - 1//2 c. n = 1, l = 1, m= 0, s = + 1//2 d. n = 1, l = 0, m= +1, s = + 1//2 e. n = 0, l = 1, m= -1, s = - 1//2 f. n = 2, l = 2, m= 0, s = - 1//2 g. n = 2, l = 1, m= 0, s = - 1//2