The momentum of a photon of frequency `50 xx 10^(17) s^(-1)` is nearly

Options

A. `1.1 xx 10^(-23) kg m s^(-1)`
B. `3.33 xx 10^(-43) kg ms^(-1)`
C. `2.27 xx 10^(-40) kg ms^(-1)`
D. None of these

Answer

A

Explanation

`lambda = (h)/(mv)` or mv =momentum
`:.` Momentum `= (h)/(lambda)` also `c = v = lambda`. Hence
Momentum `= (hv)/(c) = (6.62 xx 10^(-34) xx 50 xx 10^(17))/(3 xx 10^(8))`
`= 1.1 xx 10^(-23) kg ms^(-1)`