A near U.V. photon of 300 nm is absorbe by a gas is red then remitted as two photons. One photon is red with wavelength 760 nm. Hence wavelength of the second photon is

Options

A. 460 nm
B. 1060 nm
C. 496 nm
D. 300 nm

Answer

C

Explanation

`E = (hc)/(lambda) = (hc)/(300 nm)`
`E_(1) = (hc)/(lambda) = (hc)/(760 nm)`
`E_(2) = (hc)/(lambda)`
`E = E_(1) + E_(2)`
`(1)/(300) = (1)/(760) +(1)/(lambda)`
`(1)/(lambda) = (1)/(300) - (1)/(760)`
`= (76-30)/(22800) = (46)/(22800)`
`lambda = (22800)/(46) = 495.6 nm`