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The momentum of a particle associated wi...

The momentum of a particle associated with de-Broglie's wavelength of `6 Å` is

A

`1.1 xx 10^(-24) kg ms^(-1)`

B

`1.1 xx 10^(34) kg ms^(-1)`

C

`39.6 xx 10^(-34) kg ms^(-1)`

D

`39.6 xx 10^(-24) kg ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`mv = (h)/(lambda) = (6.62 xx 10^(-34))/(6 xx 10^(-10)) = 1.1 xx 10^(-24) kg ms^(-1)`
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