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The ratio of kinetic energy and potentia...

The ratio of kinetic energy and potential energy of an electron in a Bohr orbit of a hydrogen`-` like species is `:`

A

`1:2`

B

`-1:2`

C

`1:1`

D

`-1:1`

Text Solution

Verified by Experts

The correct Answer is:
B
K.E. `= (Ze^(2))/(2r), P.E. = -(Ze^(2))/(r) :. (K.E.)/(P.E.) = (1//2)/(-1)`
or `-1:2`
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