If wavelength of photon is `2.2 xx 10^(-11)m`, `h = 6.6 xx 10^(-34) Js`, then momentum of photons is

Options

A. `3 xx 10^(-23) kg m s^(-1)`
B. `3.33xx 10^(2) kg m s^(-1)`
C. `1.452 xx 10^(-44) kg ms^(-1)`
D. `6.89 xx 10^(43) kg m s^(-1)`

Explanation

To find the momentum of a photon given its wavelength, we can use the de Broglie wavelength formula, which relates the wavelength (λ) of a photon to its momentum (P) and Planck's constant (h). The formula is:

\[ \lambda = \frac{h}{P} \]

Where:
- \( \lambda \) = wavelength of the photon
- \( h \) = Planck's constant
- \( P \) = momentum of the photon

We can rearrange this formula to solve for momentum (P):

\[ P = \frac{h}{\lambda} \]

### Step-by-Step Solution:

1. **Identify the given values**:
- Wavelength (λ) = \( 2.2 \times 10^{-11} \, m \)
- Planck's constant (h) = \( 6.6 \times 10^{-34} \, Js \)

2. **Substitute the values into the momentum formula**:
\[ P = \frac{h}{\lambda} = \frac{6.6 \times 10^{-34} \, Js}{2.2 \times 10^{-11} \, m} \]

3. **Perform the division**:
- First, calculate the numerical part:
\[ \frac{6.6}{2.2} = 3 \]
- Now, handle the powers of ten:
\[ \frac{10^{-34}}{10^{-11}} = 10^{-34 + 11} = 10^{-23} \]

4. **Combine the results**:
\[ P = 3 \times 10^{-23} \, kg \cdot m/s \]

5. **Final answer**:
The momentum of the photon is:
\[ P = 3 \times 10^{-23} \, kg \cdot m/s \]