What will be de Broglie's wavelength of an electron moving with a velocity of `1.2 xx 10^(5) ms^(-1)` ?

Options

A. `6.068 xx 10^(-9)`
B. `3.133 xx 10^(-37)`
C. `6.626 xx 10^(-9)`
D. `6.018 xx 10^(-7)`

Answer

A

Explanation

`lambda = (h)/(mv) = (6.62 xx 10^(-34))/(9.1 xx 10^(-31) xx 1.2 xx 10^(5))`
`= 6.06 xx 10^(-9)`.