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The energy of the first electron in heli...

The energy of the first electron in helium will be

A

`-13.6 eV`

B

`-54.4 eV`

C

`-5.44 eV`

D

zero.

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(n) = -(13.6)/(n^(2)) 2^(2) eV`
`= -(-13.6)/(1^(2)) xx 2^(2) =-54.4 eV`
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