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In a hydrogen atom, if energy atom, if e...

In a hydrogen atom, if energy atom, if energy of an electron in group state is `- 13.6 eV`, then that in the `2^(nd)` excited state is :

A

`1.51 eV`

B

`3.4 eV`

C

`6.04 eV`

D

`13.6 eV`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(n) = -(13.6)/(n^(2)) eV`
Second excited state means n = 3
`E_(3) = - (13.6)/(9) - 1.51 eV`.
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