Unpaired electrons in `Ni^(++)`, (Z = 28) is

Options

A. 0
B. 2
C. 4
D. 8

Answer

B

Explanation

`Ni(Z = 28) : 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p 4s^(2) 3d^(8)`
`Ni^(2+) : 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(8)`
No. of unpaired electron = 2.