Among the following series of transition metal ions the one where all meal ions have `3d^2` electronic configuration is

Options

A. `Ti^(2+), V^(3+), Cr^(4+), Mn^(5+)`
B. `Ti^(3+), V^(2+), Cr^(3+), Mn^(4+)`
C. `Ti^(+), V^(2+), Cr^(3+), Mn^(4+)`
D. `Ti^(4+), V^(3+), Cr^(2+), Mn^(3+)`

Answer

A

Explanation

`Ti (Z = 22) : 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(2)`
`V (Z = 23) : 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(3)`
`Cr (Z = 24) : 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(1) 3d^(2)`
`Mn (Z =25) : 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(5)`
`Ti^(2+), V^(3+), Cr^(4+)` and `Mn^(5+)`, all have `[Ar]^(18) 3d^(2)` electronic configuration.