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For d-electrons, the orbital angular mom...

For d-electrons, the orbital angular momentum is

A

`sqrt(6h//2pi)`

B

`sqrt(2h//2pi)`

C

`h//2pi`

D

`2h//pi`

Text Solution

Verified by Experts

The correct Answer is:
A
Orbital angular momentum `= sqrt(l(l+1) (h)/(2pi))`
For a d-orbital, l = 2
`:.` Orbital angularn momentum of a d-electron
`= sqrt(2(2+1).(h)/(2pi)) = sqrt(6.(h)/(2pi))`
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