The wavelength of the radiation emitted , when in a hydrogen atom electron falls from infinity to stationary state 1 , would be :
(Rydberg constant = `1.097 xx 10^(7) m^(-1)`)

Options

A. 91 nm
B. `9.1 xx 10^(-8) nm`
C. 406 nm
D. 192 nm

Answer

A

Explanation

For hydrogen atom
`bar(nu) = R_(H) [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
Here `n_(2) =oo` and `n_(1) = 1`
`:. bar(nu) =R_(H)`
`(1)/(lambda) = 1.09 xx 10^(7) m^(-1)`
`lambda = (10^(-7))/(1.09) =9.17 xx 10^(-8) m = 91.7 nm`