The radius of the forst Bohr orbit of hydrogen atom is `0.59 Å`. The radius of the third orbit of `He^(+)` will be

Options

A. `8.46 Å`
B. `0.705 Å`
C. `1.59 Å`
D. `2.38 Å`

Answer

D

Explanation

For H like particles like `He^(+)`
`r_(n) = (r_(H^(n^(2))))/(Z) =(0.59 Å xx (3)^(2))/(2) =2.38 Å`