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The wavelength of spectral line in Lyman...

The wavelength of spectral line in Lyman series for electron jumping back from 2nd orbit is

A

`1162 Å`

B

`1216 Å`

C

`1362 Å`

D

`1176 Å`

Text Solution

Verified by Experts

The correct Answer is:
B
`bar(nu) = 109, 677 cm^(-1) ((1)/(1^(2))-(1)/(2^(2))) =109677 xx (3)/(4) cm^(-1) = 82258 cm^(-1)`
`lambda = (1)/(bar(v)) = (1)/(82258 cm^(-1)) = 1.216 xx 10^(-5) cm`
`= 1216 xx 10^(-8) = 1216 Å`
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