A body of mass x kg is moving with a velocity of `100 ms^(-1)`. Its de-Broglie wavelength is `6.62 xx 10^(-35)m`. Hence x is `(h = 6.02 xx 10^(-34) J s)`

Options

A. `0.1 kg`
B. `0.25 kg`
C. `0.15 kg`
D. `0.2 kg`

Answer

A

Explanation

`lambda = (h)/(mv)`
`:. 6.62 xx 10^(-35)m = (6.62 xx 10^(-34) kg m^(2))/(x xx 100 ms^(-1))`
`:. x = 0.1 kg`