Common salt obtained from sea water contains `95% NaCl` by mass. The appoximate number of molecules present in `10.0g` of the salt is

Options

A. `10^(21)`
B. `10^(22)`
C. `10^(23)`
D. `10^(24)`

Answer

C

Explanation

`NaCl` in 10 g of salt = 9.5 g
`:.` no. of molecules `= (9.5 xx 6.02 xx 10^(23))/((23+35.5))`
`= (9.5 xx 6.02 xx 10^(23))/(58.5) ~= 10^(23)`