The shortest wavelength in hydrogen spectrum of Lyman series when `R_(H)=109678 cm^(-1)` is :-

Options

A. `1002.7 Å`
B. `1215.67 Å`
C. `1127.30 Å`
D. `911.7 Å`

Answer

D

Explanation

For Lyman series, n =1 and for shortest wave length `n = prop`
`:. bar(v) = (1)/(lambda) =R_(H)[(1)/(1^(2))-(1)/(alpha^(2))] = 109678 cm^(-1)`
`lambda =(1)/(109678)cm = 911.7 xx 10^(-8) = 911.7 Å`