The ionisation energy of H atom is `13.6 eV` The inoisation energy of `Li^(2+)` law will be

Options

A. `27.2 eV`
B. `40.8 eV`
C. `54.4 eV`
D. `108.8 eV`

Answer

C

Explanation

Second ionisation of He is represented as `He^(+) +` energy `rarr He^(2+) +e^(-)`
For hydrogen like particles like `He^(+)`
`IE = E_(H) xx 2^(2) = 13.6 xx 4 =54.4 eV`