Pick out the isoelectronic structures from the following
(i) `CH_(3)^(+)` , (ii) `H_(3)O^(+)`
(iii) `NH_(3)` , (iv) `CH_(3)^(-)`

Options

A. (i) and (ii)
B. (iii) and (iv)
C. (i) and (iii)
D. (ii) (iii) and (iv)

Answer

D

Explanation

`CH_(3)^(+) = 6 + 3 - 1 =8e^(-)`
`H_(3)O^(+) =3+8 - 1 = 10 e^(-)`
`NH_(3) = 7+3=10 e^(-)`
`CH_(3)^(-) =6+3+1 = 10 e^(-)`