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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of excited state(s) for the electron in the Bohr orbit of hydrogen is(are)

A

`-3.4 eV`

B

`-4.2 eV`

C

`-6.8 eV`

D

`+6.8 eV`

Text Solution

Verified by Experts

The correct Answer is:
A
Values of energy in excited state `= -(13.6)/(n)eV` in which n = 2,3,4 etc.
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