Given `m_(e)=9.11 xx 10^(-31)kg` and `h = 6.626 xx 10^(-34)Js`, the uncertainty involved in the measuremenetof velocity within a distance of `0.1Å` is

Options

A. `5.79 xx 10^(8) ms^(-1)`
B. `5.79 xx 10^(5) ms^(-1)`
C. `5.79 xx 10^(6) ms^(-1)`
D. `5.79 xx 10^(7) ms^(-1)`

Answer

C

Explanation

`Delta x xx m xx Delta v =h//4pi`
`:. (0.1 xx 10^(-10)m) xx (9.11 xx 10^(-31) kg) xx Delta v`
`= (6.626 xx 10^(-34) kg m^(2) s^(-1))/(4 xx 3.14)`
`Delta v = (6.626 xx 10^(7))/(4 xx 3.14 xx 0.1 xx 9.1)`
`= 5.97 xx 10^(6)ms^(-1)`