An element X has IE and EA respectively 275 and 1450 kJ `mol^(-1)`. The electronegativity of element according to Pauling scale is

Options

A. 240
B. 250
C. 308
D. 402

Answer

C

Explanation

I.E.=275 kJ `mol^(-)`
E.A.1450 kJ `mol^(-1)`
Electronegativity
`x_("pauling")=(I.E.+E,A)/(193 xx2.8)=(I.E.+E.A.)/541`
`=(275+1450)/540=3.19`