The successive ionization energy values for an element X are given below:
(1) 1st ionization energy = 410 kJ `mol^(-1)` (2) 2nd ionization energy = 820 kJ `mol^(-1)` (3) 3rd ionization energy = 1100kJ `mol^(-1)` (4) 4th ionization energy = 1500 kJ `mol^(-1)` (5) 5th ionization energy =3200 kJ `mol^(-1)`
Find out the number of valence electrons for the atom X

Options

A. 1st ionization energy =410 kj `mol^(-1)`
B. 2nd ionization energy =820 kg `mol^(-1)`
C. 3rd ionization energy =110 kg `mol^(-1)`
D. 4th ionization energy =-1500 kJ `mol^(-1)`

Answer

A