The ratio of the radii of the nucleons of `._(2)^(4)He` and `._(1)^(1)H` is

Options

A. 4
B. 2
C. 3
D. 1.6

Answer

C

Explanation

The radius of nucleus `r=r_(0)xxA^(1//3)` Where `r_(0)=1.4xx10^(-13)`cm ( a constant ) and A is the mass number
`:. (r_(0)[._(2)^(4)He])/(r_(0)[._(1)^(1)H])=(r_(0)(4)^(1//3))/(r_(0)(1)^(1//3)) =4^(1//3) =1.6`