The electronic configuration of two elements `X` and `Y` are given below:
`X` = `1s^2 2s^2 2p^6 3s^2 3p^6 4s^2` and `Y`= `1s^2 2s^2 2p^6 3s^2 3p^5` The formula of the ionic compound can be formed between these elements is

Options

A. `XY`
B. `XY_(2)`
C. `X_(2)Y`
D. `XY_(3)`

Answer

B

Explanation

`(1s^(2)2s^(2)2p^(6)3s^(2)3p^(6) 3s^(2))` has two valence electrons to therefore it readily loses these electron to form `X^(2+)` than nearest noble gas configuration. Therefore, it gains one electron easily to form `Y^(-)` combine with ion of `X^(2+)` to form compound , `XY_(2)`