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Which one of the following constitutes a...

Which one of the following constitutes a group of the isoelectronic species

A

`C_(2)^(2-),O_(2)^(-),CO,NO`

B

`NO^(+),C_(2)^(2-),CN^(-),N_(2)`

C

`CN^(-),N_(2),O_(2)^(2-),CO_(2)^(2-)`

D

`N_(2),O_(2)^(-),NO^(+),CO`

Text Solution

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The correct Answer is:
To determine which option constitutes a group of isoelectronic species, we need to analyze the number of electrons in each species provided in the options. Isoelectronic species are those that have the same number of electrons. ### Step-by-Step Solution: 1. **Understanding Isoelectronic Species**: - Isoelectronic species have the same number of electrons. To find them, we need to calculate the total number of electrons for each species in the given options. 2. **Analyzing the First Option (C2^2-, O2^2-, CO, NO)**: - **C2^2-**: - Carbon (C) has an atomic number of 6, so each carbon atom has 6 electrons. - For two carbon atoms: 2 × 6 = 12 electrons. - With a 2- charge, we add 2 more electrons: 12 + 2 = 14 electrons. - **O2^2-**: - Oxygen (O) has an atomic number of 8, so each oxygen atom has 8 electrons. - For two oxygen atoms: 2 × 8 = 16 electrons. - With a 2- charge, we add 2 more electrons: 16 + 2 = 18 electrons. - **CO**: - Carbon contributes 6 electrons and oxygen contributes 8 electrons: 6 + 8 = 14 electrons. - **NO**: - Nitrogen (N) has an atomic number of 7, so it has 7 electrons. - Oxygen contributes 8 electrons: 7 + 8 = 15 electrons. - **Conclusion for First Option**: The species C2^2- has 14 electrons, O2^2- has 18 electrons, CO has 14 electrons, and NO has 15 electrons. Since they do not all have the same number of electrons, they are not isoelectronic. 3. **Analyzing the Second Option (NO^+, C2^2-, CN^-, N2)**: - **NO^+**: - Nitrogen has 7 electrons and oxygen has 8 electrons: 7 + 8 = 15 electrons. - With a +1 charge, we subtract 1 electron: 15 - 1 = 14 electrons. - **C2^2-**: - As calculated earlier, C2^2- has 14 electrons. - **CN^-**: - Carbon has 6 electrons and nitrogen has 7 electrons: 6 + 7 = 13 electrons. - With a -1 charge, we add 1 electron: 13 + 1 = 14 electrons. - **N2**: - Each nitrogen atom has 7 electrons: 2 × 7 = 14 electrons. - **Conclusion for Second Option**: NO^+ has 14 electrons, C2^2- has 14 electrons, CN^- has 14 electrons, and N2 has 14 electrons. All these species have the same number of electrons, making them isoelectronic. 4. **Final Answer**: The second option (NO^+, C2^2-, CN^-, N2) constitutes a group of isoelectronic species.

To determine which option constitutes a group of isoelectronic species, we need to analyze the number of electrons in each species provided in the options. Isoelectronic species are those that have the same number of electrons. ### Step-by-Step Solution: 1. **Understanding Isoelectronic Species**: - Isoelectronic species have the same number of electrons. To find them, we need to calculate the total number of electrons for each species in the given options. 2. **Analyzing the First Option (C2^2-, O2^2-, CO, NO)**: ...
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