The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` is

Options

A. `MngtCrgtTigtV`
B. `TigtVgtCrgtMn`
C. `CrgtMngtVgtTi`
D. `VgtMngtCrgtTi`

Answer

C

Explanation

`Ti: [Ar]^(18) 3d^(2)4s^(2) , V: [Ar]^(18) 3d^(3)4s^(2)`
`Cr:[Ar]^(18)3d^(5)4s^(1), Mn:[Ar]^(18) 3d^(5)4s^(2)`
Since ionization enthlpy increases across a period, the correct order should be
`MngtCrgtVgtTi`
But Cr with more symmetrical electronic configuration has higher second ionization enthlpy than Mn. hence the correct order is `CrgtMngtVgtTi`.