Sum of first three ionisation energies of Al is 53-03 eV `atom^(-1)` and the sum of first two ionisation energies of Na is 52 20 eV `atom^(-1)` Out of Al(II) and Na(II)

Options

A. Na(II) is more stable than Al(III)
B. Al(III) is more stable than Na(II)
C. Both are equally unstable
D. Both are equally stable

Explanation

I.E. is not only criteria for the stability of an oxidation state.