At a constant pressure, what should be the percentage increase in the temperature in kelvin for a `10 %` increase in the volume

Options

A. `10%`
B. `20%`
C. `5%`
D. `50%`

Answer

A

Explanation

Applying charle's law
`(V_(1))/(T_(1)) = (V_(2))/(T_(2)) , V_(2) = V_(1) + 0.1 V`
`T_(2) = T_(1) + (x)/(100) T_(1)`
or `(V_(1))/(T_(1)) = (V_(1) + 0.1 V_(1))/(T_(1) + 0.01x T_(1))`
or `(V_(1))/(T_(1)) = (V_(1) (1 + 0.1))/(T_(1) (1 + 0.01 x))`
or `1 + 0.01 x = 1.1`
Hence, `x = 10%`