At constant temperature `200 cm^(3)` of `N_(2)` at `720` mmHg and `400 cm^(3)` of `O_(2)` at `750` mmHg pressure are put together in a liter flask. The final pressure of mixture will be

Options

A. `111` mmHg
B. `222` mmHg
C. `333` mmHg
D. `444` mmHg

Answer

D

Explanation

`P_(N_(2)) = (200 xx 720)/(1000) = 144mm`
`P_(O_(2)) = (400 xx 750)/(1000) = 300 mm`
`:. P_("Total") = P_(N_(2)) + P_(O_(2)) = 144 + 300`
`= 444 mm`