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A football bladder contains equimolar pr...

A football bladder contains equimolar proportions of `H_(2)` and `O_(2)`. The composition by mass of the mixture effusing out of punctured football is in the ration `(H_(2) : O_(2))`

A

`1 : 4`

B

`2 sqrt2 : 1`

C

`1 : 2 sqrt2`

D

`4 : 1`

Text Solution

Verified by Experts

The correct Answer is:
A
`("Mass of " H_(2))/("Mass of " O_(2)) = sqrt(("Mol. Mass of " H_(2))/("Mol. Mass of " O_(2)))`
`(m_(H_(2)))/(m_(O_(2))) = sqrt((2)/(32)) = (1)/(4)`
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