If the collision frequency of a gas at 1 atm pressure is Z, then its collision frequency at 0.5 atm is

Options

A. 1.0 Z
B. 0.25 Z
C. 2Z
D. 0.5 Z

Answer

B

Explanation

`Z prop P^(2)` at constant T
`:. Z_(1) prop (10^(2) " and " Z_(2) prop (0.5)^(2)`
`:. (Z_(1))/(Z_(2)) = (1^(2))/((0.5)^(2)) " or " Z_(2) = 0.25 Z_(1)`