The volume of 2.89 g of carbon monoxide at `27^(@)C` and 0.821 atm pressure is

Options

A. 1.5 lit
B. 0.3 lit
C. 3 lit
D. 30 lit

Answer

C

Explanation

`PV = RT :. V = (RT)/(P) = (0.821 xx 300)/(0.821) = 30` lit
`:. 28 g` of `CO` occupy volume `= 30 lit`
2.8 g of `CO` occupy volume `= (30 xx 208)/(28) = 3`lit