In a flask of volume V litres, 0.2 mole of oxygen, 0.4 mole of nitrogen, 0.1 mole of `NH_(3)` and 0.3 mole of He are enclosed at `27^(@)C`. If the total pressure exerted by these non-reacting gases is one atmosphere, the partial pressure exerted by nitrogen is

Options

A. 1 atm
B. 0.1 atm
C. 0.2 atm
D. 0.4 atm

Answer

D

Explanation

Mole fraction of `N_(2)`
`x_(N_(2)) = (0.4)/(0.2 + 0.4 + 0.1 + 0.3) = (0.4)/(100) = 0.4`
Partial pressure of `N_(2) = x_(N_(2)) xx` Total pressure
`= 0.4 xx 1 atm = 0.4 atm`