A gas at a pressure of 5.0 atm is heated from `0^(@)C` to `546^(@)C` and simultaneously compressed to one-third of its original volume. Hence, final pressure is:

Options

A. 10.0 atm
B. 30.0 atm
C. 45.0 atm
D. 5.0 atm

Answer

C

Explanation

`P_(1) = 5 atm, " " P_(2) = ?`
`V_(1) = V mL` (say), `V_(2) = V//3 mL`
`T_(1) = 273 K, T_(2) 273 + 546 = 819 K`
`P_(2) = (P_(1)V_(1)T_(2))/(T_(1)V_(2)) = (5 xx V xx 819)/(273 xx (V//3))`
`= (5 xx 3 xx 819)/(273) = 45.0 atm`