Ideal gas equation in terms of `KE` per unit volume, `E`, is

Options

A. `P = (3)/(2) RT`
B. `P = (2)/(3) E`
C. `P = (2)/(3) RT`
D. `P = (3)/(2) E`

Answer

B

Explanation

`PV = (1)/(3) M u^(2)`
`PV = (2)/(3). (1)/(2) M u^(2)`
`PV = (2)/(3) (K.E.)`
`P = (2)/(3) ((K.E)/(V))`
`P = (2)/(3) E`.