A gas in an open container is heated from `27^(@)C` to `127^(@)C` The fraction of the original amount of gas remaining in the container will be .

Options

A. `3//4`
B. `1//2`
C. `1//4`
D. `1//8`

Answer

C

Explanation

Here P does not change
`(V_(1))/(V_(2)) = (T_(1))/(T_(2))`
`(v)/(V_(2)) = (300)/(400)`
`V_(2) = (4)/(3)v`
`:.` Amount of gas escaped
`= V_(2) - V_(1) = (v)/(4)`
thus `1//4` of the original volume of the gas will escape