100 mL `O_(2)` gas diffuses in 10 sec. 100 mL of gas X diffuses in `t` sec. Gas X and time `t` can be

Options

A. `H_(2), 2.5 sec`
B. `SO_(2), 16 sec`
C. `CO, 10 sec`
D. `He, 4 sec`

Answer

A

Explanation

Here `V_(1) = V_(2)`
`(t_(2))/(t_(1)) = sqrt((M_(2))/(M_(1))) " or " (t_(2)^(2))/(t_(1)^(2)) = (M_(2))/(M_(1))`
`t_(1) = 10s, M_(1) = 32`
`(t_(2)^(2))/(M_(2)) = (t_(1)^(2))/(M_(1))`
`(t_(1)^(2))/(M_(2)) = ((10)^(2))/(32) = (100)/(32) = (25)/(8)`
(A) `(t_(2)^(2))/(M_(2)) = ((2.5)^(2))/(2) = ((5//2)^(2))/(2) = (25)/(8)`
Thus choice (A) is correct