The van der Waal's equation of state for 1 mole real gas is `(P + (a)/(V^(2))) (v - b) = RT`....(i)
The Virial equation for 1 mole real gas is `PV = RT [1 + (x)/(V) + (y)/(V^(2)) + (z)/(V^(3))+....." To higher power of " V]` ....(ii)
when x, y and z are constants which are known as 2nd, 3rd adn 4th co-efficients respectively. The temperature at which real gas obeys ideal gas equation i.e., `(PV = nRT)` is known as Boyle's temperature.
Answer the following questions on the basis of the above write up :
The third virial coefficient of He gas is `4 xx 10^(-2)` `("litre/mole")^(2)`, then what will be volume of 2 mole He gas at NTP

Options

A. 22.0 litres
B. 44.0 litre
C. 44.8 litre
D. 45.3 litre

Answer

D

Explanation

`b^(2) = 4 xx 10^(-2)` litre/mole
i.e., `b = 2 xx 10^(-1)` litre/mole
Extended volume for 2 mole real gas.
`:. V_("real") = V_(C) + nb = 44.8 + 0.4 = 45.3` litre