At a temperature `T, K`, the pressure of `4.0 gm` argon in a bulb is `P`. The bulb is put in a bath having temperature higher by `50 K` than the first one `0.8` of argon gas had to be removed to maintain original pressure. The temperature `T` is

Options

A. 510 K
B. 200 K
C. 100 K
D. 73 K

Answer

B

Explanation

`PV = (4)/(M) RT`.....(Case I)
`PV = (3.2)/(M) R (T + 50)`.....(Case II)
`(4)/(3.2) xx (T)/(T + 50) = 1`
`4T = 3.2 T + 160`
`T = (160)/(8.0) = 200 K`