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One mole each of a monoatomic, diatomic and triatomic gases are mixed `C_(p)//C_(v)` for the mixture is

A

`1.40`

B

1.428

C

1.67

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

`C_(v) = (((3)/(2) R + (5)/(2) R + (6)/(2)R))/(3) = (7R)/(3)`
`C_(p) = (((5)/(2) R + (7)/(2) R + (8)/(2) R))/(3) = (10R)/(3)`
`(C_(p))/(C_(v)) = (10)/(7) = 1.428`
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