One mole of an ideal monoatomic gas is mixed with 1 mole of an ideal diatomic gas The molar specific heat of the mixture at constant volume is .

Options

A. 3 cal
B. 4 cal
C. 8 cal
D. 9 cal

Answer

B

Explanation

`C_(v) = (3)/(2) R` (For monoatomic gas)
`C_(v) = (5)/(2) R` (For diatomic gas)
Thus, for an equimolar mixture
`C_(v) = (((3)/(2) R + (5)/(2)R))/(2) = 2R = 4 cal`