In the fcc arrangement of `A` and `B` atoms whose `A` atoms are at corners of the unit cell and `B` are at the face centres one of the `A` atom is missing from one corner in each unit cell. What is the simplest formula of the compound?

Options

A. `A_(7)B_(3)`
B. `AB_(3)`
C. `A_(7)B_(24)`
D. `A_(7//8)B_(3)`

Answer

C

Explanation

Number of atoms A from corners of unit cell =7//8.
Number of atoms B from faces of unit cell =Thus `A:B: :7//8:3`.
`i.e.,A_(7//8)B_(3)`.Hence simplest formula is `A_(7)B_(24)`.