An alloy of copper, silver and gold is found to have copper forming the simple cubic close packed lattice. If the silver atoms occupy the face centres and gold is present at the body centre, then the formula of the alloy will be

Options

A. `Cu_(4)Ag_(4)Au`
B. `Cu_(4)Ag_(2)Au`
C. CuAgAu
D. `CuAg_(3)Au`

Answer

D

Explanation

All the eight corners of the cube are occupied by Cu atoms.
`therefore` No. of Cu atoms per unit cell `=8times1/8=1`.
No. of Ag atoms per unit cell =6(at the face centres) `times1//2=3`.
No. of Au atoms per unit cell =1
(present at the body centre of the cube).
The formula of the alloy is `CuAg_(3)Au`.